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16x^2-76x-143=0
a = 16; b = -76; c = -143;
Δ = b2-4ac
Δ = -762-4·16·(-143)
Δ = 14928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14928}=\sqrt{16*933}=\sqrt{16}*\sqrt{933}=4\sqrt{933}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-4\sqrt{933}}{2*16}=\frac{76-4\sqrt{933}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+4\sqrt{933}}{2*16}=\frac{76+4\sqrt{933}}{32} $
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